³log9+³log108-³log4+log27
Jawaban:
[tex] log_{3}(9) + log_{3}(108) - log_{3}(4) + log_{9}(27) \\ log_{3}(3 ^{2} ) + log_{3}( \frac{108}{4} ) + log_{3^{2} }(3 ^{3} ) \\ 2 + log_{3}(27) + \frac{3}{2} \\ 2 + log_{3}(3^{3} ) + \frac{3}{2} \\ 2 + 3 + \frac{3}{2} \\ \frac{13}{2} \\ 6 \frac{1}{2} [/tex]
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